пΛ✓iL.

引用:

原帖由 FaTe‧達 於 2010-11-4 19:47 發表
f(x)=x(x+1)
a.求2f(-4)  b.求f(2)+(f(-3))^2

f(x) = x(x+1)

a.求2f(-4)
2f(-4) = 2(-4)[(-4)+1]
          = 24

b.求f(2)+(f(-3))^2
f(2) = 2(2+1)
      = 6
f(-3)
= f(-3)
= -3(-3+1)
= 6

f(2)+(f(-3))^2
= 6+6^2
= 6+36
= 42